X^2+18x=319

Solution for X^2+18x=319 equation:

X^2+18X=319

We move all terms to the left:

X^2+18X-(319)=0

a = 1; b = 18; c = -319;
Δ = b2-4ac
Δ = 182-4·1·(-319)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-40}{2*1}=\frac{-58}{2}
=-29
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+40}{2*1}=\frac{22}{2}
=11
$